Question
A spring extends by 0.08 m when a force of 4.0 N is applied. The spring obeys Hooke's law. (a) Calculate the spring constant. (2) (b) Calculate the elastic potential energy stored in the spring at this extension. (2)
Mark scheme (4 marks):
- (a) k = F/e = 4.0 / 0.08 (1) = 50 N/m (1)
- (b) Ee = ½ × k × e² = 0.5 × 50 × 0.08² (1) = 0.16 J (1)
- Allow ecf from (a) into (b)
4 marks · take your time before peeking.
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Generated by TopMyGrade AI · cross-check official sources before relying on the mark-scheme phrasing.